proof 1+1 = 0 ?

Assumption:

1) i = sqrt(-1)
2) sqrt(ab) = sqrt(a) * sqrt(b)

1+1 = 1+ sqrt(1)
= 1 + sqrt( (-1) * (-1))
= 1 + sqrt(-1) * sqrt(-1) # assumption #2
= 1+ i * i # assumption #1
= 1+ sqare(i)
= 1+ sqare(sqrt(-1)) # quare root of square is same e.g. sqrt(2*2) = 2
= 1+ (-1)
= 1-1
= 0

Hence 1+1 = 0 — proved

Don’t believe? watch video below:

This entry was posted on Saturday, April 5th, 2008 at 10:57 pm and is filed under Educational, Mathematics, Science . You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

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One Response to “proof 1+1 = 0 ?”

  1. admin Says:
    April 6th, 2008 at 2:41 am

    Where is the problem in the calculation?
    let me explain you…
    the expression “= 1+ square(sqrt(-1)) ” itself is wrong…
    as we can’t get square root of -1 which is imaginary and we can’t omit “sqrt(-1)” and neutralize with square.
    so = sqare(sqrt(-1)) becomes square (imaginary number) which again becomes imaginary ….
    so the value of sqare(sqrt(-1)) can’t be calculated….

    I’ll wait for your inputs on my solution to this problem.

    Hope I learn from your inputs!
    Thanks!

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